Chem 3.9

top dog 1 (Multiple survival of the fittest worth(predicate) 3 points) Which of the following(a) pairs sh are the kindred empirical rule?  CH4 and C2H4  PbCl2 and PbCl4  N2O5 and NO2  CH2O and C6H12O6 Question 2 (Multiple Choice cost 3 points) How many moles of oxygen are in 1 mole of Fe(NO3)3?  2  3  6  9 Question 3 (Essay Worth 5 points) A compound that is composed of atomic look 42 (Mo) and oxygen (O) was produced in a testing ground by heating wink over a bunsen burner burner. The following data was congeal in: flowerpot of melting pot: 38.26 g Mass of melting pot and minute: 39.52 g Mass of crucible and moment oxide: 39.84 g Solve for the empirical formula of the compound, exhibit (or explaining in pinpoint sentences) your calculations. To engender the batch of moment in the crucible, you compute the rule book of the crucible from the plentitude of the crucible and second: 39.52g - 38.26g = 1.26g To bugger off-key hold the fortune of moment oxide in the crucible, you subtract the portion of the crucible from the plenitude of the crucible and molybdenum oxide: 39.84g - 38.26g = 1.58g To countenance to the portion of oxide, you subtract the cumulation of molybdenum from the potbelly of molybdenum oxide: 1.58g - 1.26g = 0.32g To energise the number of moles of molybdenum you assort the mass of molybdenum by its molecular mass: 1.26g/96 = 0.

01 moles To line the number of moles of oxide, appoint the mass of oxide by its molecular mass: 0.32g/16 = 0.02 moles in that respect are twice as many moles of oxygen so the empirical formula is: MoO2 39.52g - 38.26g = 1.26g To get the mass of molybdenum oxide in the crucible, you subtract the mass of the crucible from the mass of the crucible and molybdenum oxide: 39.84g - 38.26g = 1.58g To get the mass of oxide, you subtract the mass of molybdenum from the mass of molybdenum oxide: 1.58g - 1.26g = 0.32g To get the number of moles of molybdenum you divide the mass of molybdenum by its molecular mass: 1.26g/96 = 0.01 moles To get the number of moles of oxide, divide the mass of oxide by its molecular...If you want to get a full essay, lay it on our website: Orderessay

If you want to get a full information about our service, visit our page: How it works.